Answer:
transmissivity =0.0001458235 m² / year
Explanation:
given data
discharge = 6,000 acre - feet/year = 0.001775566 cubic miles
width of aquifer = 1.8 miles
Gradient = 0.95%
to find out
what would be the average transmissivity of the aquifer
solution
we know that transmissivity formula that is
transmissivity = [tex]\frac{Q}{W*i}[/tex]
here Q is discharge and W is width and i is gradient
so put here value
transmissivity = [tex]\frac{Q}{W*i}[/tex]
transmissivity = [tex]\frac{0.001775566}{1.8*0.45}[/tex]
transmissivity =0.0010383427 mile² / year
and we know 1 miles² = 2589988.11 m²
so
transmissivity =0.0001458235 m² / year