Respuesta :
Answer:
before collision a = 4.90 m/s², during collision a = -36.95 m/s² and average a3 = 2.21 m/s²
Explanation:
Before starting the problem let's reduce all the magnitude to SI units
V1 = 145 km / h (1000m / 1 km) (1h / 3600s) = 40.28 m / s
V2 = 76.5 km / h = 21.25 m / s
a) In this part we can use the kinematic equations
Vf = Vo + a t
How the vehicle starts from rest (Vo = 0)
a = Vf / t
a = 40.8 / 8.33
a = 4.90 m/s²
b) During the collision we must use the relationships and momentum and amount of movement
I = Δp
F t = m (vf-vo)
F = m (vf-Vo) / t
F = m (21.25 -40.28) /0.515
F = m (-36.95)
Now let's use Newton's second law, to look for the average acceleration
F = ma
a = F / m
a = 1/m (-36.95)m
a = -36.95 m / s²
The negative sign indicates that acceleration opposes speed
c) The magnitude of the average acceleration, to calculate this the definition of average acceleration is used, which is the change in speed between the time the change lasts
The time that the change lasts is from when the speed is zero, until reaching the maximum speed and during the crash, bone is the total time of the movement
t3 = 8.33 + 0.515
t3 = 8,845 s
ΔV = 40.8 - 21.25
ΔV = 19.55 m / s
a3 = ΔV / t3
a3 = 19.55 / 8.845
a3 = 2.21 m/s²
The initially motionless test car which is accelerated uniformly and strike a simulated deer has,
- a) The magnitude of the acceleration of the car before the collision is 4.90 m/s².
- b) The average acceleration of the car during the collision is 36.95 m/s² in the opposite direction.
- c) The magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over is 2.21 m/s².
What is the acceleration of a object?
Acceleration of a object is the rate of change of velocity of the object per unit time.
Given information-
The acceleration of the car is 145 km/h or 40.28 m/s.
The time of this acceleration is 8.33 seconds.
The car is in contact with the faux fawn for 0.515 seconds.
The velocity of the car is 76.5 km/h or 21.25 m/s.
- a) The magnitude of the acceleration of the car before the collision
Acceleration of a body is the ratio of difference of final velocity to the initial velocity to the time.
Here initial velocity of the car is zero. Thus the acceleration of the car is,
[tex]a=\dfrac{40.8}{8.33}=4.90[\tex]
Thus, the magnitude of the acceleration of the car before the collision is 4.90 m/s².
- b) The magnitude of the average acceleration of the car during the collision-
The speed before the collision was 40.28 m/s and after the collision 21.25 m/s.
Thus the average acceleration of the car is,
[tex]a=\dfrac{21.25-40.28}{0.515}=-36.95\rm m/s^2[/tex]
The average acceleration of the car during the collision is 36.95 m/s² in the opposite direction.
c) The magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over-
The average acceleration of the car during the entire test is the ratio of difference of initial speed and final speed to the total time.
[tex]a=\dfrac{40.8-21.5}{8.33+0.515}=2.21\rm m/s^2[/tex]
Hence, the magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over is 2.21 m/s².
Hence,
The initially motionless test car which is accelerated uniformly and strike a simulated deer has,
- a) The magnitude of the acceleration of the car before the collision is 4.90 m/s².
- b) The average acceleration of the car during the collision is 36.95 m/s² in the opposite direction.
- c) The magnitude of the average acceleration of the car during the entire test, from when the car first begins moving until the collision is over is 2.21 m/s².
Learn more about the acceleration here;
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