Question

An open box is formed by cutting squares with side lengths of 5 inches from each corner of a square piece of paper. what is the side length of the original paper if the box has volume of 1445 cubic inches?

A.22 inches
B.24 inches
C. 27 inches
D.29 inches

Answer 1

24 inches

hope it helps!

and I oop-

Answer 2

Answer:

Option C - 27 inches

Step-by-step explanation:

Given : An open box is formed by cutting squares with side lengths of 5 inches from each corner of a square piece of paper.

To find : What is the side length of the original paper if the box has volume of 1445 cubic inches?

Solution :

The volume of the box is $V=L\times B\times H$

We have given V=1445 cubic inches.

Since, 5 inches were cut from each corner of the square piece of paper,

So, H=5 inches

Since, the original paper is square and the length cut from each side is the same, the resulting base is still square.

So, L=B

Substitute the values in the formula,

$1445=L\times L\times 5$

$L^2=\frac{1445}{5}$

$L^2=289$

$L=\sqrt{289}$

$L=17$

Since we folded the paper from each side, we need to add the length of opposite sides (i.e. 2 instances) of the folded part to get  the original length.

The length of the original paper is l=17+5+5=27 inches.

Therefore, the side length of the original paper is 27 inches.

So, Option C is correct.