Calculate the total mass of water in kg on Earth's surface from the following data: total planetary surface area: 510,066,000 km2, land area of planet: 148,647,000 km2 , assume the average depth of water is:100.0km and the density of water is 1.00g/mL

(using dimensional analysis)

Respuesta :

Answer:

The total mass of water in on Earth's surface is [tex]3.61419\times 10^{22} kg[/tex].

Explanation:

Total planetary surface area = T = [tex]510,066,000 km^2[/tex]

Total land area of planet = L = [tex]148,647,000 km^2[/tex]

Total water area of planet = W

T = L + W

[tex]510,066,000 km^2=148,647,000 km^2-W[/tex]

[tex]W=510,066,000 km^2-148,647,000 km^2=361,419,000 km^2[/tex]

Volume = Area × Depth

Volume of water on earth = V

V= [tex]361,419,000 km^2\times 100 km^=36,141,900,000 km^3[/tex]

[tex]km^3=10^{12} L[/tex]

[tex]V=36,141,900,000 km^3=36,141,900,000 \times 10^{12} L[/tex]

Total mass of total water on the earth = M

Density of the water,D = 1 g/mL = 0.001 kg/0.001 L=1 kg/L

1 g - 0.001 kg

1 mL = 0.001 L

[tex]D=\frac{M}{V}[/tex]

[tex]M=D\times V[/tex]

[tex]M =1 kg/L\times 36,141,900,000 \times 10^{12} L=3.61419\times 10^{22} kg[/tex]

The total mass of water in on Earth's surface is [tex]3.61419\times 10^{22} kg[/tex].