Question

A student performs a titration by dispensing 24.6 mL of 0.10 M NaOH into a 35.5 mL sample of HCl. Calculate molarity of HCl solution

Answer 1

Answer:

Molarity of HCl is 0.07 M.

Explanation:

Given data:

Molarity of NaOH =0.10 M

Volume of NaOH= 24.6 mL

Molarity of HCl = ?

Volume of HCl = 35.5 mL

Solution:

M (HCl) × V (HCl) = M (NaOH) × V (NaOH)

M (HCl) = M (NaOH) × V (NaOH) /  V (HCl)

M (HCl) = 0.10 M × 24.6 mL / 35.5 mL

M (HCl) = 2.46 M / 35.5

M (HCl) = 0.07 M