Respuesta :

tear1220

Answer:30

Step-by-step explanation:

There are three parts that need to calculate each and combine together.

270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6)

    (1 )               (2)                 (3)

(1) 270 ÷ 9=30

(2) (27+13)÷8 ⋅ 2=40÷8 ⋅ 2=5 ⋅ 2=10

(3) 2 ⋅ (11–6)=2 ⋅ 5=10

(1)+(2)-(3)=30+10-10=30

Answer:

270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 30

Step-by-step explanation:

The order of operation is written as BODMAS

               BO - Bracket open

                  D - Division

                  M - Multiplication

                  A - Addition

                   S - Subtraction

We need to find 270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6)

Let us open the brackets first

                  270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 270 ÷ 9+(40)÷8 ⋅ 2–2 ⋅ (5)  

                   270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) =   270 ÷ 9+40÷8 ⋅ 2–2 ⋅ 5

Now let us do the division part

                    270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 30 + 5 . 2 -2 . 5    

Now let us do the multiplication part

                    270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 30 + 10 -10

Now let us do the addition part

                    270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 40 -10

Now let us do the subtraction part

                    270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 30

So 270 ÷ 9+(27+13)÷8 ⋅ 2–2 ⋅ (11–6) = 30

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