Answer and Solution:
As per the question:
Given:
If [tex]A\subseteq B\cup C[/tex]
[tex]A\cap B = \phi[/tex]
To prove:
[tex]A\subseteq \C[/tex]
Proof:
Suppose [tex]t\in A[/tex]
As we know that:
[tex]A\subseteq B\cup C[/tex]
Therefore,
[tex]t\in B[/tex] or [tex]t\in C[/tex]
Now, if we assume that [tex]t\in B[/tex]
Then
[tex]t\in A\cap B[/tex]
Since,
[tex]t\in A[/tex] and [tex]t\in B[/tex]
But
A and B are disjoint set and [tex]A\cap B = \phi[/tex]
Therefore, this is contradictory.
Thus
[tex]t\notin B[/tex]
So,
[tex]t\in C[/tex]
Every element in the set A is also present in the set C
Therefore, [tex]A\subseteq \C[/tex]
Hence, proved.