Question

Factor the difference of cubes 1331x3 - 8

Answer 1

Formula: (x-y)(x²+xy+y²)     ---    x = 11x, y = 2

(11x-2)(121x²+22x+4)

Answer 2

Answer:

$\bold{(11 x-2)\left(121 x^{2}+22 x+4\right)}$

Given:

$1331 x^{3}-8$

Step-by-step explanation:

In this problem, we need to find the factors of the given expression.

The factors of a given number/expression are the numbers/expressions which results in given number on multiplying.

The given expression is in an algebraic expression which is:

$x^{3}-y^{3}=1331 x^{3}-8$

On giving the cube forms,

$\Rightarrow x^{3}-y^{3}=(11 x)^{3}-(2)^{3}$

Now, the factored form of the above expression is:

$x^{3}-y^{3}=(x-y)\left(x^{2}+x y+y^{2}\right)$

Now,

$\therefore(11 x)^{3}-(2)^{3}=(11 x-2)\left(121 x^{2}+22 x+4\right)$

The above given is the factor for the given difference in the cube.