Question

A football player kicks a ball with an initial
velocity of 25 meters per second at an angle of
53° above the horizontal. The vertical component
of the initial velocity of the ball is
A.
25 m/s
B,
D.
20. m/s
10. m/s
C.
15 m/s

Answer 1

Answer:

20 m/s

Explanation:

The vertical component of the initial velocity of the ball is given by:

$v_y = v_0 sin \theta$

where:

$v_0$ is the initial speed

$\theta$ is the angle of launch above the horizontal

In the problem we have

$v_0 =25 m/s\\\theta=53^{\circ}$

Substituting into the equation,

$v_y = (25)(sin 53^{\circ})=20 m/s$

Answer 2

Answer:

The vertical component  of the initial velocity of the ball is 20 m/s.

Explanation:

Given data:

Initial velocity is, u = 25 m/s.

Angle of inclination is, $\theta = 53 ^{\circ}$.

The vertical component of initial velocity is,

$v = usin \theta$

Solving as,

$v = 25 \times sin53\\v \approx 20 \;\rm m/s$

Thus, vertical component  of the initial velocity of the ball is 20 m/s.

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https://brainly.com/question/13639113?referrer=searchResults