Question

If you used 0.75 grams of p-aminophenol and got 0.74 grams of acetaminophen, what is the percent yield?

Answer 1

Answer:

Percent yield is 71,2%

Explanation:

Acetaminophen is produced by p-aminophenol thus:

p-aminophenol + acetic anhydride → acetaminophen

The moles of p-aminophenol are:

$0,75g*\frac{1 mol}{109,14 g}$ = 6,87x10⁻³ moles

As molar ratio between p-aminophenol and acetaminophen is 1:1; the moles of acetaminophen with a theoretical yield are 6,87x10⁻³ moles, thus, theoretical grams are:

6,87x10⁻³ moles×$\frac{151,163g}{1mol}$ = 1,04 grams

As percent yield is real yield/theoretical yield times 100:

$\frac{0,74}{1,04} *100$ = 71,2%

I hope it helps!