Question

(1.) An object accelerates from rest with a constant acceleration of 2 m/s2. How far will it have
moved after 9s?

Answer 1

Answer:

81 m

Explanation:

Given:

v₀ = 0 m/s

a = 2 m/s²

t = 9 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (9 s) + ½ (2 m/s²) (9 s)²

Δx = 81 m