Answer: The mass of water produced is 1.8 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of ethanol = 4.59 g
Molar mass of ethanol = 46.07 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ethanol}=\frac{4.59g}{46.07g/mol}=0.0996mol[/tex]
The chemical equation for the reaction of ethanol with oxygen gas follows:
[tex]CH_3CH_2OH+O_2\rightarrow CH_3COOH+H_2O[/tex]
By Stoichiometry of the reaction;
1 mole of ethanol produces 1 mole of water.
So, 0.0996 moles of ethanol will produce = [tex]\frac{1}{1}\times 0.0996=0.0996mol[/tex] of water.
Now, calculating the mass of water from equation 1, we get:
Molar mass of water = 18 g/mol
Moles of water = 0.0996 moles
Putting values in equation 1, we get:
[tex]0.0996mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.0996mol\times 18g/mol)=1.8g[/tex]
Hence, the mass of water produced is 1.8 grams