Question

Assuming complete distribution, what is the molarity of 10 milligrams of lisinopril in 100 liters?

Answer 1

Answer:

$2.47x10^{-7}   M$

Explanation:

Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:

• First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.

$10mg*\frac{1g}{1000mg}=0.01g$

• Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.

$\frac{1mol}{405.488g}*\frac{0.01g}{100L}=2.47x10^{-7}   M$

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