Question

Blood Alcohol Content (BAC) is sometimes reported in weight-volume percent and, when it is, a BAC of 0.10% corresponds to 0.10 g ethyl alcohol per 100 ml of blood. In many jurisdictions, a person is considered legally intoxicated if his or her BAC is 0.10%. Suppose that a 68 kg person has a total blood volume of 5.4 L and breaks down ethyl alcohol at a rate of 10.0 grams per hour. How many145 ml glasses of wine, consumed over three hours, will produce a BAC of 0.10% in his 68 kg person?

Answer 1

Answer:

2,3 glasses of wine.

Explanation:

In three hours, to produce a BAC of 0,10%  for a 68kg person (5,4L blood) you need to consume:

$\frac{0,10 gEthylAlcohol}{100mL blood} * 5400mLBlood+10,0g/h*3h$ = 30,54g of ethyl alcohol

Assuming a 11,6% (v/v) of wine Where density of ethyl alcohol is 0,789 g/mL:

$30,54gEthylAlcohol*\frac{1mL ethanol}{0,789g} \frac{100mLwine}{11,6 mL ethanol}$ = 333,7 mL wine

Thus, the person need to consume:

$\frac{333,7 mL wine}{145mL}$ = 2,3 glasses of wine