Answer:
2.5 grams of of water is consumed by the reaction of 6.2 g of carbon dioxide.
Explanation:
[tex]6H_2O+6CO_2\rightarrow C_6H_{12}O_6+6O_2[/tex]
Moles of carbon dioxide = [tex]\frac{6.2 g}{44 g/mol}=0.1410 mol[/tex]
According to reaction , 6 moles of carbon dioxide reacts with 6 moles of water.
Then 0.1410 moles of carbon dioxide will react with:
[tex]\frac{6}{6}\times 0.1410 mol=0.1410 mol[/tex] of water.
Mass of 0.14109 moles of water = 0.1410 mol × 18 g/mol = 2.536 g ≈ 2.5 g
2.5 grams of of water is consumed by the reaction of 6.2 g of carbon dioxide.