Question

What is the balanced net ionic equation including phases for K2SO4 and SrI2

Answer 1

Answer:

Sr 2+(aq) + SO42-(aq) → SrSO4(s)

Explanation:

Step 1: Write a properly balanced equation with states:

K2SO4(aq) + Srl2(aq) → 2KI(aq) + SrSO4(s)

Step 2: write the full ionic equation with states. Remember to keep molecules intact. Only states (aq) will dissociate,  (s) will not dissociate . This means SrSO4 won't dissociate.

2K+(aq) + SO42-(aq) + Sr 2+(aq) + 2I-(aq) → 2K+(aq) + 2I-(aq) + SrSO4(s)

Step 3: Balanced net ionic equation

Sr 2+(aq) + SO42-(aq) → SrSO4(s)

Answer 2

We have that for the Question "What is the balanced net ionic equation including phases for K2SO4 and SrI2" it can be said that its balanced net ionic equation  is

$Sr^{2^+}(aq)+S0_4^{2-}_{aq} ---- SrSO_4$

From the question we are told

What is the balanced net ionic equation including phases for K2SO4 and SrI2

Generally

K2SO4 known as Potassium Sulfate

SrI2 known as  Strontium iodide

Where there Molecular equation

$K2SO4 (aq)+SrI_2(aq) ---- 2KI_(aq) +SrSO_4(s)$

Hence its balanced net ionic equation  is

$Sr^{2^+}(aq)+S0_4^{2-}_{aq} ---- SrSO_4$

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