Answer:
The factored form of [tex]16x^{2} - 16x - 12 \text { is } 4(2x - 3)(2x + 1)[/tex]
Solution:
From question, given that [tex]16x^{2}-16x-12[/tex]
To factorize the given expression, follow the below steps:
[tex]16x^{2}-16x -12[/tex]---- eqn 1
Taking 4 as a common term in equation 1, we get
[tex]=4\left(4 x^{2}-4 x-3\right)[/tex]
“4x” can be rewritten as –6x+2x. Now the above equation becomes,
[tex]=4\left(4 x^{2}-6 x+2 x-3\right)[/tex]
By taking 2x as common from [tex]4x^{2}-6x[/tex], the above equation becomes,
[tex]=4[2x(2 x-3)+1(2 x-3)][/tex]
[tex]=4(2 x-3)(2 x+1)[/tex]
Hence the factor of [tex]16 x^{2}-16 x-12 \text { is } 4(2 x-3)(2 x+1)[/tex]
