Two public works employees are installing a wheelchair ramp near the steps of a public library. The main door to the library is 6 feet off the ground. Assuming the horizontal distance of the ramp is 24.8, what is the length of the ramp? Round to the nearest tenth of a foot.​

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Answer:

Two public works employees are installing a wheelchair ramp near the steps of a public library. The length of the ramp is 25.51 feet.

Solution:

Consider the diagram attached below.

Let AB be ground. C be the position of main door.

As horizontal distance of the ramp = 24.8 feet

So AB = 24.8 feet

Main door of the library is 6 feet off the ground.

So CB = 6 feet

Need to calculate length of the ramp that is AC.

By Pythagoras theorem, square of one side of a right triangle is equal to sum of square of other two sides.

On applying Pythagoras theorem in right triangle ABC, we get

[tex]AC^{2}=A B^{2}+B C^{2}[/tex]

[tex]AC=\sqrt{A B^{2}+B C^{2}}[/tex]

On substituting value of AB and BC,

[tex]AC=\sqrt{(24.8)^{2}+(6)^{2}}[/tex]

[tex]=\sqrt{615.04+36}[/tex]

[tex]=\sqrt{651.04}[/tex]

= 25.51 feet

Hence length of the ramp is 25.51 feet.

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