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02-10-2019
Chemistry

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One cubic meter of an ideal gas at 600 K and 1000 KPa expand to five times its initial volume as follows:

(a) By a mechanically reversible, isothermal process [T 2 = 600K; P 2 = 200kPa; W= -1609 kJ]

(b) By a mechanically reversible, adiabatic process [T 2 =208.96K; P 2 = 67.65 kPa; W= -994.4 kJ] For each case calculate the final temperature, pressure and the work done by the gas. C p =21 Jmol- 1K-1.

Respuesta :

sasukesaad9 sasukesaad9

02-10-2019

Answer:

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Explanation:lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

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