Answer:
[tex]m_w = 449.04 kg/hr[/tex]
Explanation:
Given data:
air stream temp 32.2 degree celcius
steam heater is at 65.5 degree celcius
flow of air 1000 kg mol/h
we know that [tex]C _{AIR}[/tex] = 29.2 Kj/KG-MOL
Saturated stream is at 148.9 and from steam table hg is 2745.12 kJ/kg
saturated water us 148.9 degree and from steam table hf = 627.46 kJ/kg
then cooled to saturated water with temperature 137.8 degree celcius and hf = 579.71 kJ/kg
from energy balanced
[tex]mC\Delta T \for\ air = mC\Delta H [/tex]
[tex]1000\times 29.2\times (65.5 -32.2) = m_w\times (2745.12 - 579.71)[/tex]
solving for m_w
[tex]m_w = 449.04 kg/hr[/tex]