Racing cars A and B are traveling on circular portions of a race track. At the instant shown, the speed of A is decreasing at the rate of 8 m/s2, and the speed of B is increasing at the rate of 3 m/s2. For the positions shown, determine (a) the velocity of B relative to A, (b) the acceleration of B relative to A.

Respuesta :

Answer:

a) [tex]V_{B/A} = V_B - V_A[/tex]

b) [tex]a_{B/A} = 11m/s^2[/tex]

Explanation:

Since we don't have any diagram or image, I will make these assumptions in order to be able to answer the questions:

- They are moving in a straight line

- They both move in the same direction

With these assumptions we can say that their velocities have the same sign, so the velocity of B relative to A would be:

[tex]V_{B/A} = V_B - V_A[/tex]  If, for example, Vb = 20m/s and Va = 30m/s then:

[tex]V_{B/A} = -10m/s[/tex] This would be the answer for part (a)

If they both move in the same direction, their accelerations would be:

[tex]a_A = -8m/s^2[/tex]    and   [tex]a_B = 3m/s^2[/tex]  So, the acceleration of B relative to A would be:

[tex]a_{B/A} = a_B - a_A = 3 - (-8) = 11m/s^2[/tex]