Question

I WILL AWARD BRAINLIEST!! PLEASE HELP!! Given: ΔDEK, DE = EK EF - ∠bisector of ∠E m∠DEF = 44°, DK= 16 KF = ____ cm, m∠DEK = _____, m∠DFE = _______

Answer 1

I believe this is correct

m∠DEK = 2*m∠DEF

m∠DEK = 2*43°

m∠DEK = 84°

KF = = DK/2

KF = 16/2

KF = 8 cm

m∠EFD = 90°