Answer:
[tex]\Delta q = 2\times 10^{-3} C[/tex]
Explanation:
As we know that electric current is defined as the rate of flow of charge
so here we can say that
[tex]i = \frac{dq}{dt}[/tex]
so charge flow through it is given as
[tex]\Delta q = i \Delta t[/tex]
here we know that
i = 1 A
[tex]\Delta t = 2 ms[/tex]
so total charge flow is given as
[tex]\Delta q = 1\times (2\times 10^{-3})[/tex]
[tex]\Delta q = 2\times 10^{-3} C[/tex]