Answer:
Slope of a line which is parallel the line passes through (-3,2) and (0,-2) is [tex]\frac{-4}{3}[/tex]
Solution:
Slope of the line which is passes through [tex]\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)[/tex] is
[tex]\bold{m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}}[/tex] ---- eqn 1
From question given that two points are (-3, 2), (0,-2). Hence we get
[tex]x_{1}=-3 ; x_{2}=0 ; y_{1}=2 ; y_{2}=-2[/tex]
By substituting the values in equation (1),
[tex]m=\frac{-2-2}{0+3}[/tex]
On simplifying above term,
[tex]m=\frac{-4}{3}[/tex]
If two lines are parallel then slope of both lines should be equal. That is slope of the line which passes through (-3,2) and (0,-2) is [tex]\frac{-4}{3}[/tex] . so slope of a line which is parallel the line passes through (-3,2) and (0,-2) is also [tex]\bold{\frac{-4}{3}}[/tex]
