A cubical Gaussian surface surrounds two positive charges, each has a charge q 1 1 = + 3.90 × 10 − 12 3.90×10−12 C, and three negative charges, each has a charge q 2 2 = − 2.60 × 10 − 12 2.60×10−12 C as the drawing shows. What is the electric flux passing through the surface?(The permittivity of free space ε 0 0 = 8.85×10-12C²/(N.m²))

Respuesta :

Answer:

The electric flux is zero because charge is zero.

Explanation:

Given that,

Positive charge [tex]q_{1}=3.90\times10^{-12}\ C[/tex]

Negative charge [tex]q_{2}=-2.60\times10^{-12}\ C[/tex]

We need to calculate the total charged

Using formula of charge

[tex]Q_{enc}=2q_{1}+3q_{2}[/tex]

Put the value into the formula

[tex]Q_{enc}=2\times3.90\times10^{-12}+3\times(-2.60\times10^{-12})[/tex]

[tex]Q_{enc}=0[/tex]

We need to calculate the electric flux

Using formula of electric flux

[tex]\phi=\dfrac{Q_{enc}}{\epsilon_{0}}[/tex]

Put the value into the formula

[tex]\phi=\dfrac{0}{8.85\times10^{-12}}[/tex]

Hence, The electric flux is zero because charge is zero.