Answer:
a)θ=74.03° (N-E)
b)t=1.56 hr
Explanation:
Given that
Plane speed = 200 km/h
Wind speed = 55 km/h
Now from diagram
V is the resultant velocity of plane
[tex]200^2=V^2+55^2[/tex]
V=192.28 km/h towards north
From triangle ABC
[tex]cos\theta =\dfrac{55}{200}[/tex]
θ=74.03°
Given that
d=300 km
We know that
d = V x t
300 = 192.28 x t
t=1.56 hr