Answer:
In sample A,
The percentage of thymine or T is 20.5 %. A = T, so the percentage of A will also be 20.5 %.
Thus, A + T = 20.5 + 20.5 = 41 %
Therefore, G + C = 100 - 41 = 59 %
So, G = 59 /2 = 29.5 %
Also. G = C = 29.5 %
In sample B,
The percentage of Thymine or T is 30.7 %. As A = T, so A will also be 30.7 %.
Thus, A + T = 30.7 + 30.7 = 61.4 %
Also, G + C = 100 - 61.4 = 38.6 %
So, G = 38.6 / 2 = 19.3 %
Therefore, C will also be 19.3 %. As GC content is more found in the sample A, that is, 59 %. Hence, the sample A will possess the higher temperature to denature in comparison to B.