Respuesta :
Answer:
Explanation:
Given parameters:
Energy output = 30units
Energy input = 100units
problem:
Energy efficiency of light bulb:
Solution:
Efficiency is given as:
Efficieny = \frac{energy_{output} }{energy_{input } x100
Efficieny = [tex]\frac{30}{100}[/tex] x 100 = 30%
Answer:
The correct answer is option a.
Explanation:
Efficiency is defined as the ratio of output energy to input energy.
Efficiency(e)=[tex]\frac{E_o}{E_i}[/tex]
Energy given out by the system = [tex]E_o[/tex]
Energy given to the system = [tex]E_i[/tex]
Here we are given with : [tex]E_o-30 units,E_i=100[/tex]
Efficiency of of a light bulb:
[tex]e=\frac{30 units}{100 units}=0.3 [/tex]