Question

Women aged 70 to 79 are, of course, not young adults. The mean BMD in this age group is about −2 on the standard scale for young adults. Suppose that the standard deviation is the same as for young adults. What percent of this older population has osteoporosis?

Answer 1

30.85% of this older population has osteoporosis.

What is Osteoporosis?

Osteoporosis may be defined as a circumstance in which there is a reduction in the amount and thickness of bone tissue.

The percentage of the older population that has osteoporosis is calculated as follows with the help of a normal distribution table.

P(Z<-2.5- (-2)) = P(Z<-0.5)

The value of Z must be lower than 0.5 but greater than 0.25

Therefore, according to the standard normal table, the value of standard deviation falls under 0.3085

where P= probability

Z= Standard deviation.

= 0.3085 (Using standard normal table).

∴ Percentage = 0.3085 × 100 = 30.85%

Therefore, 30.85% of this older population has osteoporosis.

To learn more about Osteoporosis, refer to the link:

https://brainly.com/question/7924115

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