Question

The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recorded. Which animal moves with non-accelerated motion? Time at Distance Markers Animal 25 meters 50 meters 75 meters Animal 1 3 seconds 4.5 seconds 5 seconds Animal 2 4.5 seconds 5 seconds 5.25 seconds Animal 3 3.5 seconds 7 seconds 10.5 seconds Animal 4 5 seconds 10 seconds 13 seconds Animal 1 Animal 2 Animal 3 Animal 4

Answer 1

Answer: Animal 3

Explanation:

Acceleration $a$ is defined as the variation of Velocity $\Delta V$ in time $\Delta t$:  

$a=\frac{\Delta V}{\Delta t}$

In this sense, with the data given in table 1 (figure attached) we can calculate each animal's velocity at each distance marker. Knowing velocity $V$ is defined as the variation of position $\Delta d$ in time $\Delta t$:  

$V=\frac{\Delta d}{\Delta t}$

Since we already have the position (with the distance markers) and the time at that point, we can make the calculations for each one:

Animal 1:

$V_{1}=\frac{25 m}{3 s}=8.33 m/s$

$V_{2}=\frac{50 m}{4.5 s}=11.1 m/s$

$V_{3}=\frac{75 m}{5 s}=15 m/s$

Animal 2:

$V_{1}=\frac{25 m}{4.5 s}=5.55 m/s$

$V_{2}=\frac{50 m}{5 s}=10 m/s$

$V_{3}=\frac{75 m}{5.25 s}=14.28 m/s$

Animal 3:

$V_{1}=\frac{25 m}{3.55 s}=7.14 m/s$

$V_{2}=\frac{50 m}{7 s}=7.14 m/s$

$V_{3}=\frac{75 m}{10.5 s}=7.14 m/s$

Animal 4:

$V_{1}=\frac{25 m}{5 s}=5 m/s$

$V_{2}=\frac{50 m}{10 s}=5 m/s$

$V_{3}=\frac{75 m}{13 s}=5.76 m/s$

As we can see after the results of each calculation (table 2 in figure attached) the velocity remains the same with Animal 3, which means ther is no acceleration. Hence, Animal 3 moves with non-accelerated motion.

Answer 2

Answer:

b

Explanation:

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