Answer:
For the first reaction: Ca (s) + Cl2 (g) ⇒ CaCl2
For second reaction: Ca (s) + 2HCl (aq) ⇒ CaCl2 (aq) + H2 (g)
Explanation:
1) First you have to write the equations that describes the synthesis of calcium chloride from calcium (Ca) and chlorine (Cl2). The overall reaction can be separated in two semi-reactions, the oxidation of calcium and the reduction of chlorine.
Ca (s) ⇒ Ca+2 + 2e- (oxidation)
Cl2 (g) + 2 e- ⇒ 2Cl- (reduction)
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Ca (s) + Cl2 (g) + 2e- ⇒ CaCl2 (s) + 2e- (overall reaction)
Summarizing Ca (s) + Cl2 (g) ⇒ CaCl2
2) In the second part you must consider the reaction of Calcium and hydrochloric acid to form aqueous calcium chloride.
Ca (s) ⇒ Ca+2 + 2e-
2HCl (aq) ⇒ 2H+ (aq) + 2Cl- (aq)
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Ca (s) + 2HCl (aq) ⇒ CaCl2 (aq) + H2 (g)