Question

A person suffering from hyponatremia has a sodium ion concentration in the blood of 0.117 M and a total blood volume of 4.9 L . Part A What mass of sodium chloride would need to be added to the blood to bring the sodium ion concentration up to 0.138 M, assuming no change in blood volume

Answer 1

Answer:

We should add 6.017g of NaCl to bring the sodium ion concentration to 0.138M

Explanation:

Step 1: Data given

Concentration of sodium in the blood is 0.117 M → 0.138 M

Blood volume = 4.9 L

Concentration = moles /liter

Step 2: Calculate number of moles

moles = concentration * Volume

For this problem we have: moles = 0.117 M * 4.9 L = 0.5733 moles

Step 3: Calculating mass of Na in the blood

Molar mass of NaCl = 58.44 g/mole

0.5733 moles * 58.44 g/mole = 33.50g of NaCl in 4.9L blood

Step 4: Calculate moles of sodium required

To have a concentration of 0.138 we need:

0.138 M * 4.9 L = 0.6762 moles

Step 5: Calculate mass of Na required

0.6762 moles * 58.44 g/mole = 39.517g of NaCl required

Step 6: Calculate mass needed to increase concentration of sodum from 0.117M to 0.138 M

39.517 - 33.50 = 6.017 g NaCl

We should add 6.017g of NaCl to bring the sodium ion concentration to 0.138M