Answer:
The 8 isomers are drawn in the image:
1) 1-bromopentane
2) 2-bromopentane
3) 3-bromopentane
4) 1-bromo-2-methylbutane
5) 1-bromo-3-methylbutane
6) 2-bromo-2-methylbutane
7) 2-bromo-3-methylbutane
8) 1-bromo-2,2-dimethylpropane
1), 4), 5) and 8) are primary alkyl halides (alkyl bromides).
2), 3) and 7) are secondary alkyl halides (alkyl bromides).
6) is a tertiary alkyl halide (alkyl bromide).
Explanation:
Primary alkyl halides have the halogen (bromine) attached to a primary carbon, that is, a carbon that is attached to a single carbon (and two hydrogens).
Secondary halides have the halogen (bromine) attached to a secondary carbon, that is, a carbon that is attached to two carbons (and a hydrogen).
Tertiary halides have the halogen (bromine) attached to a tertiary carbon, that is, a carbon that is bonded to three carbons (and no hydrogen).