A committee of three people is selected at random from a set consisting of six ​teachers, five parents of​ students, and seven alumni. a. What is the probability of the event that the committee consists of all​ teachers? b. What is the probability of the event that the committee has no​ teachers?

Respuesta :

Answer:

0.0245 and 0.2696

Step-by-step explanation:

Given that there are six ​teachers, five parents of​ students, and seven alumni.

A committee of three people is selected at random from the above set

Without any condition, we see that total number of selecting three persons from these 18 persons is [tex]18C3 =\frac{18(17)(16)}{3!} =816[/tex]

a) the committee consists of all​ teachers

No of ways of selecting all teachers from 6 teachers = [tex]6C3 = 20[/tex]

Probability of the event that the committee consists of all​ teachers

=[tex]\frac{20}{816} =0.0245[/tex]

b)  the committee has no​ teachers

This is equivalent to selecting 3 persons from 12 non teachers

= [tex]12C3=220[/tex] ways

the probability of the event that the committee has no​ teachers=[tex]\frac{220}{816} =0.2696[/tex]