Answer:
the probability that exactly 30 of the 500 calculators IS 0.0495
Explanation:
Given data:
number of calculators n = 500,
percentage of defected calculators p = 0.05
From Normal approximation method;
[tex] X~Normal mean = 500\times 0.05 = 25,[/tex]
[tex]s = \sqrt{n\times p\times (1-p)}[/tex]
[tex]= \sqrt{(500\times 0.05\times 0.95)} = 4.87 [/tex]
Therefore probability is
P(X= 30) = P(29.5< X< 30.5) ( from continuous correction)
[tex] =P[\frac{(29.5-25)}{4.87}] < \frac{(X-mean)}{s} < \frac{(30.5-25)}{4.87}
=P(0.92<Z< 1.13) [/tex]
=0.0495 (from standard table of Z )