Answer:
Probability of viewing television between 5 to 10 hr is 0.6553
Step-by-step explanation:
Given data:
total time period of viewing of per household = 8.35 hr
standard deviation = 2.5 hr
Probability between 5 to 10 hr can be obtained as
= P(Between 5 and 10 hours)
[tex]= P(\frac{(5 - 8.35)}{2.5} < z < \frac{(10 - 8.35)}{2.5})[/tex]
= P(-1.34 < z < 0.66)
= P(z < 0.66) - P(z < -1.34)
determine z value from standard z table
= 0.7454 - 0.0901
= 0.6553