Answer:
B. The balls reach the ground at the same instant.
Explanation:
M = Mass of Earth = 5.972×10²⁴ kg
r = Radius of Earth = 6.371×10⁶ m
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
[tex]ma=G\frac{Mm}{r^2}\\\Rightarrow a=G\frac{M}{r^2}\\\Rightarrow a=6.67\times 10^{-11}\frac{5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81364\ m/s^2[/tex]
From the equation above it can be seen that all objects irrespective of mass falls at the same acceleration.
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0t+\frac{1}{2}\times 9.81364\times t^2\\\Rightarrow t=\sqrt{\frac{2s}{9.81364}}[/tex]
If both bodies are initially at rest and travel the same distance the time the bodies will take to reach the ground will be same.