Respuesta :
Choices:
y=4x-1
y=2/7x
y=7/2x
y=7/x
(2,7) ⇒ x = 2 ; y = 7
y = 4x - 1 ⇒ y = 4(2) - 1 ; y = 8 - 1 ; y = 7
y = 2/7x ⇒ y = 2/7(2) ; y = 2/14 ; y = 1/7
y = 7/2x ⇒ y = 7/2(2) ; y = 7/4 ; y = 1 3/4
y = 7/x ⇒ y = 7/2 ; y = 3 1/2
Among the choices, only y = 4x - 1 is the direct variation that contains the ordered pair (2,7)
y=4x-1
y=2/7x
y=7/2x
y=7/x
(2,7) ⇒ x = 2 ; y = 7
y = 4x - 1 ⇒ y = 4(2) - 1 ; y = 8 - 1 ; y = 7
y = 2/7x ⇒ y = 2/7(2) ; y = 2/14 ; y = 1/7
y = 7/2x ⇒ y = 7/2(2) ; y = 7/4 ; y = 1 3/4
y = 7/x ⇒ y = 7/2 ; y = 3 1/2
Among the choices, only y = 4x - 1 is the direct variation that contains the ordered pair (2,7)
The direct relation that is a direct variation that contains the ordered pair (2, 7) is; y = (7/2)x
How too work with direct variation?
Given ordered pair is (2, 7)
We know that y = kx is valid for every direct relationship,
Determine k using the y and x, since k = y/x
k = 7/2
k = 3.5
Put the value for k in y = kx and you have y = 3.5x.
Therefore, the direct relation that is a direct variation that contains the ordered pair (2, 7) is y = (7/2)x
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