Answer:0.154
Step-by-step explanation:
Given
Let factory A produces 2c unit
B produces 7c units
C produces c units
Probability a computer is chosen from A is [tex]\frac{2}{10}[/tex]
[tex]From B=\frac{7}{10}[/tex]
[tex]from C=\frac{1}{10}[/tex]
Probability Of a defective computer [tex]=\frac{2}{10}\times 0.035+\frac{7}{10}\times 0.048+\frac{1}{10}\times 0.046=0.0452[/tex]
Probability that it came from factory A [tex]=\frac{\frac{2}{10}\times 0.035}{\frac{2}{10}\times 0.035+\frac{7}{10}\times 0.048+\frac{1}{10}\times 0.046}=0.154[/tex]