Answer:
The equation in slope intercept form having slope of 2 and passes through the point A(-3,-1) is given as 2x - y + 5 = 0.
Solution:
In geometry we know the standard form of slope intercept form is y = mx + c. where “m” stands for the slope of the equation, “c” stands for the intercept.
Let us consider the point [tex]\left(x_{1}, y_{1}\right)[/tex]. A straight line passing through that point having the slope of m is given as
[tex]\bold{y - y_{1} = m\left(x - x_{1}\right)}[/tex]
In the given question, the point A(-3,-1) has the slope of 2.
Hence we get m = 2 and [tex]x_{1} = -3 ; y_{1} = -1[/tex]
The equation for the line in slope-intercept form is given as
y - (-1) = 2(x - (-3))
y + 1 = 2(x + 3)
y + 1 = 2x + 6
Rearranging the terms, we get
2x – y + 6 -1 = 0
2x – y + 5 = 0
Hence the equation in slope-intercept form of the line that has slope 2 and passes through point A(-3, -1) is 2x – y + 5= 0.
