Respuesta :
Answer:
To minimize the time spent to achieve the goal, Goldilocks
must spend 4 days and a half in mine 1 and 3 days in mine 2
Step-by-step explanation:
Let's call x the number of days Goldilocks spends on mine 1 and y the number of days it spends on mine 2 to meet the requirements.
Then
2x + y is the amount of gold found in both mines and
2x + 3y is the amount of silver found in both mines
We have the constraints
a) 2x + y≥ 12
b) 2x + 3y ≥ 18
and we want to minimize the total time spent to accomplish this goal. That is, we want to find x and y such that
x+y is minimum.
We then draw in the xy-plane the regions a) and b) and find the feasible region which is the intersection of both regions
(SEE PICTURE ATTACHED)
The line 2x + y =12 (GREEN) has x-intersect x=6 and y-intersect y=12
The line 2x + 3y =18 (BLUE) has x-intersect x=9 and y-intersect y=6
The point P is the intersection (x,y) of the two lines, that is, the result of solving the linear system
2x + y = 12
2x + 3y = 18
The solution of this system can easily be found and gives us
P=(4.5, 3)
As the function z = x + y is linear, its minimum is attained in one of the vertices (0,12), (9,0) or (4.5,3).
A direct evaluation of z in each one this points, gives as a result that the minimum is reached in (4.5,3)
So, to minimize the time spent to achieve the goal, Goldilocks
must spend 4 days and a half in mine 1 and 3 days in mine 2.
