Question

Line j passes through point (2, 0) and is perpendicular to the graph of y = x - 3. Line k is parallel to line j and passes through point(-1,6). What is the equation in slope-intercept form of line k?

Answer 1

Answer:

y = - x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x - 3 ← is in slope intercept form

with slope m = 1

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{1}$ = - 1, thus

y = - x + c ← is the partial equation of line j

To find c substitute (2, 0) into the partial equation

0 = - 2 + c ⇒ c = 0 + 2 = 2

y = - x + 2 ← equation of line j

Parallel lines have equal slopes, thus

y = - x + c ← is the partial equation of line k

To find c substitute (- 1, 6) into the partial equation

6 = 1 + c ⇒ c = 6 - 1 = 5

y = - x + 5 ← equation of line k