Question

3x+y=8________(1) and x²+xy=6________(2) solve this​

Answer 1

Answer:

In first equation if we put the value of x and y (x=2,y=2)than,

3x+y=8

3×x+y=8

3×2+2=8

6+2=8

8=8

in second equation the value of x=2,y=1

x2+xy=6

x2+x×y=6

4+2×1=6

4+2=6

6=6

Answer 2

Answer:

$[3, -1] \\ [1, 5]$

Step-by-step explanation:

{3x + y = 8 >> y = -3x + 8

{x² + xy = 6

${x}^{2} + x[-3x + 8] = 6 \\ {x}^{2} -3{x}^{2} + 8x = 6 \\ -2{x}^{2} + 8x = 6 \\ \\ -2{x}^{2} + 8x - 6 \\ [-2{x}^{2} - 6x] - [2x - 6] \\ \\ -2x[x + 3] - 2[x + 3] \\ \\ -[2x + 2][x + 3] = 0 \\ \\ 1, \: 3 = x$

You plug these back into both equations above to get both y-coordinates of -1 and 5:

$-1, \: 5 = y$

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