Answer:
There are [tex]3,1536*10^{7}[/tex] seconds in a year.
The fractional error in assuming [tex]1yr=\pi * 10^{7} sec[/tex] is [tex]3,81*10^{-3}[/tex].
Step-by-step explanation:
Assuming a year of 365 days (non leap-years), we can found how many seconds are in a year by multiplying seconds in a minute, minutes in an hour, hours in a day and finally days in a year.
[tex]Seconds_{year} = 60\frac{seconds}{minute} *60\frac{minutes}{hour}*24\frac{hours}{day} *365\frac{days}{year}=3,1536*10^{7} \frac{seconds}{year}[/tex]
Knowing how many seconds are in a year, we can find the absolute error of the estimation by taking the module of the difference between real value and estimation:
[tex]\varepsilon _{abs} = |real value-estimation|=|3,1536*10^{7} \frac{seconds}{year}-\pi *10^{7} \frac{seconds}{year}|=1,2000734641 *10^{5}\frac{seconds}{year}[/tex]
Now that we know the absolute error, we calculate the fractional error by dividing it by the real value:
[tex]\varepsilon _{rel}=\frac{\varepsilon _{abs}}{real value}= \frac{1,2000734641 *10^{5} \frac{seconds}{year}}{3,1536*10^{7} \frac{seconds}{year}}=3,81 *10^{-3}[/tex]
That is a minimal error, close to 0,4% and enough for every day estimations.