Answer:
True
Step-by-step explanation:
Given that recurrence formula is
[tex]a_k = 2a_{k-1} -3\\,k>2\\[/tex] and
[tex]a_1 =4[/tex]
From this we can find
[tex]a_2 = 2a_1-3\\= 8-3 =5\\a_3 =2(5)-3 =7\\a_4 = 2(7)-3 = 11\\[/tex]
Let us check now R's for these numbers
R(1) is trivially true
[tex]R(2) = 2^{2-1} +3 =5\\R(3) = 2^{3-1} +3 =7\\R(4) = 2^{4-1} +3 =11[/tex]
We find that these matches with a values we found using recurrence formula
Hence we can say that R(1), R(2), R(3), and R(4) are true