Answer:
(x,y,z) = (1+s, 2-2s,3-7s)
Step-by-step explanation:
Given that a line in three dimension passes through two points a and b
We have equation of the line passing through two points
[tex](x_1,y_1,z_1) \\(x_2,y_2,z_2)[/tex] is
[tex]\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1} =\frac{z-z_1}{z_2-z_1}[/tex]
Substitute for the two points and equate to s
[tex]\frac{x-1}{2-1} =\frac{y-2}{0_2} =\frac{z-3}{-4-3}=s[/tex]
Simplify to write
[tex]\frac{x-1}{1} =\frac{y-2}{-2} =\frac{z-3}{-7} =s\\x=1+s: y= 2-2s: z=3-7s[/tex]
Thus parametric form is
(x,y,z) = (1+s, 2-2s,3-7s)