Answer:
{a,b}, {a,c} , {a,d}, {b,c}, {b,d}, {c, d}
Step-by-step explanation:
If we have P({a, b, c, d}) where P is the power set, we know that there are 6 two elements sets in P (because this is the number of combinations of two elements taken from 4 elements, [tex]C_{4|2}=(4)(3)/2=12/2 = 6[/tex]
These 6 sets would be: {a,b}, {a,c} , {a,d}, {b,c}, {b,d}, {c, d}