Answer:
When n is gamma: [tex]n = \gamma= \cfrac{C_p}{C_v}[/tex]
Also known as the heat capacity ratio.
Explanation:
For an ideal gas of constant heat capacity, if we want an adiabatic process, that is, a process in which there is no entropy change, we will have the following relation:
[tex]dU = T dS - Pd V\\dS= 0 \implies dU= -PdV[/tex]
But we also know that [tex]dU = C_v dT[/tex]
Moreover, we have by the ideal gas law:
[tex]PV= NR\, T\\VdP + PdV = NR \, dT[/tex]
Now, if we eliminate dT from the last equations, we get:
[tex]VdP + P dV = NR\, \Big( -\cfrac{P dV}{C_v}\Big)[/tex]
If we act algebraically on this, we get:
[tex]\Big( 1 + \cfrac{NR}{C_v} \Big) \cfrac{dV}{V}+ \cfrac{dP}{P}=0[/tex]
Now, the coeffcient on the left :
[tex]1 + \cfrac{NR}{C_v} = \cfrac{C_v+NR}{C_v } = \cfrac{C_p}{C_v} = \gamma[/tex]
Where we have made use of so called Mayer's relation for an ideal gas:
[tex]C_p= C_v + NR[/tex]
Going back to our last equation, we find:
[tex]\gamma \cfrac{dV}{V}+ \cfrac{dP}{P}=0\\[/tex]
We can integrate this and get:
[tex]\gamma \ln V + \ln P = K\\\ln (P\, V ^\gamma ) = K\\\\PV^\gamma = C[/tex]
Where K and C are just integration constants.