Answer:
HV = 372.4 KGf/mm^2
[tex]HR_C = 39.445[/tex]
Explanation:
given data:
minimum tensile strength = 1240 MPa
we knwo that [tex]\sigma_{vrs}[/tex] and brinell hardness number (HB} relation given as
[tex]\sigma_{vrs} = 3.4 \times H.B[/tex]
[tex]H.B = \frac{1240}{3.4} = 364.7[/tex]
1) relation betwen H.B and Rockwell is
[tex] HR_C = 6.96 + 0.089 HB[/tex]
[tex]HR_C = 6.96 + (0.089\times 365} = 39.445[/tex]
2) relation between HB and Vickers hardnes HV is given as
[tex]HB \times 1.05 = HV + 10.5[/tex]
[tex]HV = HB\times 1.05 - 10.5[/tex]
HV = 372.4 KGf/mm^2