Respuesta :
Answer:
The ultimate tensile strength for steel is 0.145lb/in^2 and 1.45×10^-4 kip/in^2.
And fot aluminum is 0.0101lb/in^2 and 1.017×10^-5 kip/in^2.
Explanation:
First we are going to calculate the tensile strength for steel.
The exercise says that the tensile strength for steel is 100 N/m^2. To express this numer in lb/in^2, we using a convertion char. According to the chart we can say : 1lb= 4.44 N and 1 in = 0.0254 m.
So using multiplication and divisions ⇒[tex]\frac{100N}{m^{2} } *\frac{1lb}{4.44N} *\frac{(0.0254m)^{2} }{(1in)^2}[/tex] = 0.145 lb/in^2.
Using again the converstion chart we deduce that 1 kip= 1000lb. So we have to divide the 0.145lb/in^2 with 1000lb to express this numer in kip/in^2.
⇒ [tex]\frac{0.145lb}{in^{2} } *\frac{1 kip}{1000lb}[/tex]= 1.45×10^-4 kip/in^2.
To conclude, 100N/m^2 = 0.145lb/in^2 = 1.45×10^-4 kip/in^2.
Now for the aluminum we use the same convertions to express 70N/m^2 in lb/in^2.
⇒[tex]\frac{70N}{m^{2} } *\frac{1lb}{4.44N} * (\frac{0.0254m}{1in} )^{2}[/tex]= 0.0101 lb/in^2.
and to express this in kip/in^2 :
⇒ 0.0101lb/in^2 * 1kip/1000lb= 1.017×10^-5 kip/in^2.
In conclusion, 70N/m^2 = 0.0101lb/in^2 = 1.017×10^-5 kip/in^2.
